dayofyear
description
Syntax
INT DAYOFYEAR(DATETIME date)
获得日期中对应当年中的哪一天。
参数为Date或者Datetime类型
example
1. mysql> select dayofyear('2007-02-03 00:00:00');
2. +----------------------------------+
3. | dayofyear('2007-02-03 00:00:00') |
4. +----------------------------------+
5. | 34 |
6. +----------------------------------+
keywords
1. DAYOFYEAR
